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Mathematics 8 Online
OpenStudy (mopsy510):

HELP! THIS IS ALGEBRA 1 HW! A rocket is launched from atop a 101 foot cliff with an initial velocity of 116 ft/s. a) Substitute the values into the vertical motion formula h= -16t^2 + vt + h ( with a bottom exponent of 0). Let h(t) = 0 b) Use the quadratic formula to find out how long the rocket will take to hit the ground after it is launched. Round to the nearest tenth of a second.

OpenStudy (anonymous):

start with \[h(t)=-16t^2+116t+101\]

OpenStudy (anonymous):

btw \(v_0\) and \(h_0\) are called "v zero" and "h zero" respectively

OpenStudy (mopsy510):

How did you get 101 there? It was \[h _{0}\]

OpenStudy (mopsy510):

Ohh

OpenStudy (anonymous):

in your case \(v_0=116\) and \(h_0=101\) they are the initial values, what you get when \(t=0\)

OpenStudy (mopsy510):

So v = 116 and h=101?

OpenStudy (anonymous):

yes

OpenStudy (mopsy510):

So the 0 on the bottom doesnt do anything?

OpenStudy (anonymous):

it is just notation for the initial velocity and the initial height

OpenStudy (mopsy510):

Ohh ok

OpenStudy (anonymous):

not like an exponent, just means what you get if \(t=0\) in other words when you start counting

OpenStudy (mopsy510):

So now i substitute t for 0?

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