I was sick the last 2 days of calc and missed this in class. Could somebody help me with this problem? f(x)=(x^2)-6 when x=0. Find the value of where is discontinuous and also Find the value of where is nondifferentiable.

Question

I was sick the last 2 days of calc and missed this in class. Could somebody help me with this problem?
f(x)=(x^2)-6 when x<0 and f(x)=-6 when x>=0.
Find the value of  where  is discontinuous
and also
Find the value of  where  is nondifferentiable.

anonymous · Answer

plug 0 into both functions and you get -6, so it's not discontinuous anywhere

anonymous · Answer

plug 0 into both derivatives and they are both 0, so it's differentiable everywhere