Find the quotient of -40x^3-12x^2+16x/-4x

Question

anonymous · Answer

A. 10x^2 + 3x − 4
B. −40x^3 − 12x^2 − 4
C. −10x^2 + 3x − 4
D. 10x^2 − 3x + 4

harsimran_hs4 · Answer

you can cancel out x from numerator and denominator and denominator
and then divide numerator by -4(this is what is left in the denominator after x gets canceled out)

harsimran_hs4 · Answer

can you proceed now?

anonymous · Answer

I don't really know what the 'numerator' and 'denominator' are.

harsimran_hs4 · Answer

oops that is what i did not expect it`s taught way back in 2 or 3rd grade or even earlier
e.g
$$\frac{ a }{ b }$$
here a is numerator and b is denominator

anonymous · Answer

I know haha I remember learning about it I just hadn't heard it be used since then so I didn't remember. Now how do you cancel out x?

harsimran_hs4 · Answer

-40x^3-12x^2+16x/-4x  = -40x^2-12x+16/-4 = 10x^2 + 3x -4
clear??

anonymous · Answer

yes, thank you!

harsimran_hs4 · Answer

:)