How in the world do I solve 6^4√2-14^3√2+5^3√2+7^4√2
:( my answer choices are
a) 13^4√-9^3√4
b) 13^4√2-9^3√2
c) 4√2
d) 4√4

Question

How in the world do I solve 6^4√2-14^3√2+5^3√2+7^4√2
:( my answer choices are 
a) 13^4√-9^3√4
b) 13^4√2-9^3√2
c) 4√2
d) 4√4

anonymous · Answer

Woah

anonymous · Answer

Yea... Algebra 2 online is aweful

anonymous · Answer

try using pemdas, just work through it i guess

amistre64 · Answer

you can start by changing all the sqrt(2) parts to something more readable like a or b or something

amistre64 · Answer

are those sqrts in the exponent?

anonymous · Answer

That doesnt make an sense :( I'm so confusedd !! the exponent is infront of the square root sign

amistre64 · Answer

$$ 6^{4a}-14^{3a}+5^{3a}+7^{4a}$$

amistre64 · Answer

or
$$ 6^4a-14^3a+5^3a+7^4a$$???

anonymous · Answer

$$6^{4}\sqrt{2}-14^{3}\sqrt{2}+5^{3}\sqrt{2}+7^{4}\sqrt{2}$$

amistre64 · Answer

ahh, then since i cleaned it up with as, you can factor it out and you can modify the base exponent stuff with logs most likely

anonymous · Answer

logs...?

amistre64 · Answer

$$6^4a-14^3a+5^3a+7^4a$$
$$a(6^4-14^3+5^3+7^4)$$
getting all this in like base terms is useful, and thats what logs can do

maybe

amistre64 · Answer

or, expand them all out and add em up

amistre64 · Answer

since i got no idea what level of material and study you are at, im pretty much looking at this thru my own concepts

anonymous · Answer

Algebra 2...

anonymous · Answer

Would my answer be letter B?

amistre64 · Answer

anonymous · Answer

D: but nothing is matching my answer choices!!

anonymous · Answer

I'm just going to guess on this one :(

amistre64 · Answer

6^4−14^3+5^3+7^4 = 1028

which option equals 1028 if you ignore the sqrt