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Find the derivative of the function f(x) = x^3 - 2x + 1.
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@jazy can u help? @mathsmind ?
by definition or the normal way?
f'(x) = 3x^2-2
by solving it how would i do it?
normal way you can say
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nx^(n-1)
the answer is up there
f'(x) = 3x^2-2
ok?
Is this clear?
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so how did you get f'(x) = 3x^2 - 2?
you need to know this by heart
there is no -2
ok
we use the normal method nx^n-1
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for example x^10, diff, 10x^(10-1)
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