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Mathematics 17 Online
OpenStudy (anonymous):

there are 3 ducks in a zoo and Ana has 3 pieces of food. she'll give 2 pieces to one duck and 1 piece to another duck. how many ways could she distribute her food in this manner? :)

jimthompson5910 (jim_thompson5910):

Let's call the ducks A, B and C say duck A gets the two pieces of food. So that leaves 2 ways to give the last piece of food to either B or C If B is the duck that gets two pieces, then there are still 2 ways but now A and C get the last piece Finally, if C gets the two pieces, then A or B get the last piece. So there are 2+2+2 = 6 ways to distribute the food

OpenStudy (anonymous):

omg sorry i read the question wrong. there are 13 ducks, not 3 u.u

jimthompson5910 (jim_thompson5910):

ok the same logic will apply, it'll just be a bigger answer

jimthompson5910 (jim_thompson5910):

say you had ducks A through M (thirteen ducks total) If duck A gets the two pieces, then you have 12 ways to give the last piece of food to the other ducks (B through M) If duck B gets the two pieces, then you have 12 ways to give the last piece of food to the other ducks (A through M, skipping duck B) If duck C gets the two pieces, then you have 12 ways to give the last piece of food to the other ducks (A through M, skipping duck C) etc etc, you get the picture So you will have 12 ways for each duck and there are 13 ducks, which means there are 12*13 = 156 ways to do this

OpenStudy (anonymous):

got it :) thank you so much

jimthompson5910 (jim_thompson5910):

np

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