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derivative of y y=ln9x answer is 1/x but I thought it was 1/9x d(lnu) = u' / u so why is u "x" and not "9x"?
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Because of the chain rule. After you have 1/(9x) you multiply by d/dx(9x) which is 9. So 9/9x becomes 1/x
or you can note that \(\ln(9x)=\ln(9)+\ln(x)\) and since \(\ln(9)\) is a constant, the derivative is \(\frac{1}{x}\)
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