Question

-24>8t interval notation?

Answer 1

\[
-24\gt 8t\implies -3>t\implies -\infty < t < -3
\]This is written as: \[
t\in (-\infty,-3)
\]

Answer 2

\[
a<x<b\implies x\in(a,b)\\
a \leq x<b\implies x\in[a,b)\\
a<x\leq b\implies x\in(a,b]\\
a \leq x \leq b\implies x\in[a,b]
\]

Answer 3

Notice how \(\leq\ \geq\) corresponds to \([\ ]\) and how \(\lt\ \gt\) corresponds to \((\ )\)

Answer 4

When there is no lower or upper bound, you have to use \(\infty\) and \(-\infty\) to show your boundaries. They will always be used with \((\ )\) next to them because they should be excluded from the interval.