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Mathematics 29 Online
OpenStudy (anonymous):

Please help me!?! Explain, in complete sentences, how you would completely factor 2x3 – 24x2y + 12xy – 144y2 by using the grouping method. How would you check your factors for accuracy

OpenStudy (anonymous):

first i would divide the whole equation by 2

OpenStudy (anonymous):

2x^3 - 24x^2y + 12xy - 144y^2 = 2x^2(x - 12y) + 12y(x - 12y) = (2x^2 + 12)(x - 12y)

OpenStudy (anonymous):

You can multiply out the above factors to see if you get the original polynomial.

OpenStudy (anonymous):

how did you get 2x^2 instead of 3?

OpenStudy (anonymous):

I factored out 2x^2 from the first 2 terms, then I factored out 12y from the other 2 terms. After doing that, from the Distributive Property, you can factor out x - 12y to get the answer

OpenStudy (skullpatrol):

@magenxoxo did you understand that?

OpenStudy (anonymous):

uhm. sort of.. I didnt mean to bump this question. :)

OpenStudy (e.cociuba):

First I'd factor 2x^2 from the first two terms, then 12y from the last two terms. This would leave me with (x-12y) in each factor, which I'd then factor out to get (2x^2 - 12y)(x - 12y). Then I'd factor out a 2 from the first term.

OpenStudy (anonymous):

Thanks E :)

OpenStudy (e.cociuba):

np:) Do u get it?

OpenStudy (anonymous):

yeah(:

OpenStudy (e.cociuba):

k! :)

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