Question

Help please

Just explain what to do with this inequality please

Answer 1

Would you multiply both sides by (2x+3)^2?

Answer 2

I have done that and this is the answers i get
\[x> \frac{ 7 }{ 2 } , x < \frac{ 3 }{ 2 }\]

\[x< - \frac{ 13 }{ 2 }, x> -\frac{ 3 }{ 2 }\]

Answer 3

according to wolfram answer is
http://www.wolframalpha.com/input/?i=1+%3C+%284x-4%29+%2F+%282x%2B3%29+%3C+3

Answer 4

@.Sam. @hartnn Help please

Answer 5

@ash2326 @ParthKohli @Directrix Help please?

Answer 6

divided 2 cases :
case I :
1 < (4x-4)/(2x+3)
solve for x

case II :
(4x-4)/(2x+3) < 3
solve for x too

then find intersection of both

Answer 7

yea i done that.\[x< - \frac{ 13 }{ 2 }, x> -\frac{ 3 }{ 2 }, x> \frac{ 7 }{ 2 } , x < \frac{ 3 }{ 2 }\]

Answer 8

and these are the 4 answers that i got and the real answer is this
http://www.wolframalpha.com/input/?i=1+%3C+%284x-4%29+%2F+%282x%2B3%29+%3C+3

But i dont understand how to get to that.

Answer 9

1<(4x-4)/(2x+3) or
(4x-4)/(2x+3) > 1
(4x-4)/(2x+3) - 1 > 0
(4x-4-2x-3)/(2x+3) > 0
(2x-7)/(2x+3) > 0
----(-3/2)------(7/2)------
x<-3/2 or x>7/2

case II :
(4x-4)/(2x+3) < 3 or
(4x-4)/(2x+3) - 3 < 0
(4x-4-6x-9)/(2x+3) < 0
(-2x-13)/(2x+3) < 0
(2x+13)/(2x+3) > 0
-----(-13/2)-----(-3/2)------
x < -13/2 or x > -3/2