In the equation y = ab(x – h) + k, how does the value of k affect the graph

Question

amistre64 · Answer

lets assume ab(x-h) = 0 for all cases

how does y=k get effected for chages in k ?

anonymous · Answer

im confused

anonymous · Answer

im confused

zehanz · Answer

Imagine how you would calculate y: you set x at a certain value, and then you do all kinds of calculations. The LAST thing you do, is add k. Then you draw the graph.
If k changes, then you don't have to do all the calculations again, you just add another number. If you think a while about this, you'll know what will happen with the graph...

amistre64 · Answer

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zehanz · Answer

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Look at this graph. It would be the graph for k=0. (In reality it would have d different shape, but that is not important here).
So y = ab(x-h).
Now what would you do if you had to draw y=ab(x-h) + 2? 
You wouldn't do every calculation again, just adding 2 to the y-values of this graph would be enough. Do this with every point of the graph. What happens?