Question

A(-1,1), B(3,3), C(6,2) lie on the circumference of a circle. Find the Center of the circle.

Answer 1

The equation of a circle centered at (h, k) is given by
\[(x-h)^2+(y-k)^2=r^2\]
Given the points A, B, and C, you have the following system of equations:
\[\begin{cases}(-1-h)^2+(1-k)^2=r^2\\
(3-h)^2+(3-k)^2=r^2\\
(6-h)^2+(2-k)^2=r^2\end{cases}\]Think you can solve that? (By the way, I haven't done a problem like this in a long time, so there may or may not be an easier way.)

Answer 2

Thanks a lot for the help I'll get back with the answer.

Answer 3

Ive looked out but it is apparently a straight line questions

Answer 4

Which equation is straight line's ?