Question

Help on algebra 2 questions!!!! :(





what are the roots of y=(x-3)^2-5

Answer 1

Roots also means zeroes. SO you're trying to find the zeros of this equation. What does x equal.

Answer 2

Hold on I lost it. :/

Answer 3

is it 5?

Answer 4

First make y=0

Answer 5

could you make the equation into 0=(x-3)(x-3)-5 ??

Answer 6

You could, but it's easier in the other form.\[0=(x-3)^{2}+5\]

then subtract 5 on both sides

Answer 7

sorry its supposed to be subtract 5, so add 5 on both sides

\[5=(x-3)^{2}\]

Answer 8

ok so then would you square root it ?

Answer 9

YES

Answer 10

2.23= (x-3)?

Answer 11

Okay sure, but remember when you have a square root like the one on 5. Remember it has an invisible +/- sign

Answer 12

\[x-3=\pm \sqrt{5}\]

Answer 13

so then you add 3 ? so the answer can be negative and positive?

Answer 14

Because remember the fact that the equation has a degree of 2. SO you have 2 zeroes.

Answer 15

Well when do \[3-\sqrt{5}\] it's still positive.

Answer 16

Some teachers want you to stop there. or subtract

Answer 17

If they want you to the you will get

x=0.76 and x=5.23

Answer 18

But because you estimated the decimals. It isn't exact. SO i would leave it in the square root form.

Answer 19

OOHHHH! ok!!!!!! thank you!!!!!! :)

Answer 20

You're very welcome.