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Mathematics 18 Online
OpenStudy (anonymous):

Anyone want to check my answers...? Please?

OpenStudy (anonymous):

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

What? Both answers look funky.

OpenStudy (anonymous):

\[ \log_c(a/b) = \log_c(a)-\log_c(b) \]

OpenStudy (anonymous):

OHHH now i see....

OpenStudy (anonymous):

\[ \log_c(a^b) = \underbrace{\log_c(a)+\log_c(a) +...+\log_c(a)}_{b\text{ times}} = b\log_c(a) \]

OpenStudy (anonymous):

What about my second answer? I couldn't really log it correctly but i ended up getting that

OpenStudy (whpalmer4):

As @wio said, \[\log_c(a^b) = b \log_c (a)\] What would that make the correct answer be for the second question?

OpenStudy (anonymous):

Sorry just refreshed the page....

OpenStudy (whpalmer4):

Answer?

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