Two polygons are congruent and the perimeter of the first polygon is 54 cm. If the sides of the second polygon are consecutive integers (x, x+1, x+2, x+3, etc.), what value of x makes the polygons into congruent quadrilaterals? Use x as the smallest side.

Question

harsimran_hs4 · Answer

since the polygons are congruent their permeters will also be same
so perimeter of second is :
sum of all the sides
x+ (x+1) + (x+2) + (x+3) = 4x + 6

4x + 6 = 54
can you solve for x?