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solve: a^5 + 6a^4 + 5a = 0
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a= -1, a = 0
a^5 + 6a^4 + 5a^3 = 0 First, factor out the a^3 term a^3 * (a^2 + 6a + 5) = 0 Next, we need factors of 5 that add up to 6, easy because 5 is prime... a^3 * (a + 1)(a + 5) = 0 Your values that make this true are a=0, a=-1, a=-5
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