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Calculus1
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Determine the slope of x^(2/3)+y^(2/3)=5 at the point (8,1)
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\[x^\frac{2}{3}+y^\frac{2}{3}=5\\ \frac{d}{dx}\left[x^\frac{2}{3}+y^\frac{2}{3}\right]=0\\ \frac{2}{3}x^{\frac{2}{3}-1}+\frac{2}{3}y^{\frac{2}{3}-1}\frac{dy}{dx}=0\] Solving for dy/dx, you get an expression in terms of x and y. Plug in x = 8 and y = 1, and the resulting dy/dx is the slope you're looking for.
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