Find the line that contains the point P = (2,6) and is parallel to the line y = -4x + 26
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hartnn (hartnn):
can you find slope of line y = -4x + 26 ?
OpenStudy (christos):
ok
hartnn (hartnn):
just compare it to y=mx+c , where m is the slope.
OpenStudy (christos):
-4
hartnn (hartnn):
yes.
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hartnn (hartnn):
now parallel lines have same slope, so the slope of your line will also be -4, right ?
OpenStudy (christos):
hmm yea
OpenStudy (christos):
m will be same
hartnn (hartnn):
now u have a point and slope, can you find the equation ?
OpenStudy (christos):
I see lets try
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hartnn (hartnn):
know the point slope form of equation of line ? or should i mention it ?
OpenStudy (skullpatrol):
Making a sketch may help.
OpenStudy (christos):
y=mx+b I replace y and x with 2 and 6 ? but then I would replace b too with 6 and there would be no equation, so I would do y=-4x+6 but that is still not the answer
OpenStudy (christos):
or it is indeed the answer ;p
OpenStudy (christos):
nah its not
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hartnn (hartnn):
the form is y-y1 = m (x-x1)
where point x1,y1 = 2,6 and m=-4
OpenStudy (christos):
isn't it y = mx + b ?
hartnn (hartnn):
thats slope intercept form :y=mx+b
you have a point and slope , so, y-y1 = m (x-x1)
OpenStudy (christos):
I see
OpenStudy (skullpatrol):
"but then I would replace b too with 6" here is your mistake... you are solving for b in y=mx+b
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OpenStudy (christos):
yea thats what I did indeed
OpenStudy (skullpatrol):
You do not replace b with 6
hartnn (hartnn):
because 'b' is y-intercept which is not given.
OpenStudy (christos):
I got y = mx - 2m +6
OpenStudy (skullpatrol):
You replace y with 6
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hartnn (hartnn):
yes, just put m=-4 because you know it!
OpenStudy (christos):
:D
OpenStudy (christos):
y = -4x + 14 its correct :))
hartnn (hartnn):
:D
good work!
OpenStudy (christos):
thanks
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hartnn (hartnn):
welcome ^_^
OpenStudy (christos):
now I have a similar one that is perpendicular this time instead of parallel
OpenStudy (christos):
I guess in that case m is not the same to work with that
hartnn (hartnn):
so you need to know that product of slopes of perpendicular lines = -1
hartnn (hartnn):
just to find slope.
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OpenStudy (christos):
when you say "the product" of slopes you mean m1 + m2 = -1 ?
hartnn (hartnn):
product = multiplication :P
m1 * m2 = -1
OpenStudy (christos):
aaah I see ok ^^
OpenStudy (whpalmer4):
It might be easier to think that the second slope will be -1/m if m is the slope of the first line...
OpenStudy (whpalmer4):
Completely equivalent to @hartnn's statement, but easier for some to grasp...
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