Question

PreCalc & Trig, picture below, please show your work..
Really frustrated with this homework. :/

Answer 1

use sinx=2sin(x/2)cos(x/2) then factorize

Answer 2

Maybe I should tell you this: I haven't been in class for over a week. I don't know any of this stuff.. so be as simple and thorough as you can, thanks.

Answer 3

\[\cos(\frac{ x }{ 2 })-sinx=0\]
use the identity sin2x=2sinxcosx
\[\cos(x/2)-2\sin(x/2)\cos(x/2)=0\]
\[\cos(x/2)(1-\sin(x/2))=0\]
cos(x/2)=0 or 1-sin(x/2)=0
\[\cos(x/2)=0 => x/2=\pi/2 \]
\[x=\pi\]
\[1-\sin(\frac{ x }{ 2 })=0\]

Answer 4

\[\sin(\frac{ x }{ 2 })=1 => \frac{ x }{ 2 }=\pi/2\]
\[x=\pi\]

Answer 5

the solution is \[\pi\]

Answer 6

okay, thank you.