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Find the first six terms of the sequence. a^(1) = -4, an = a^(n-1) + 7 -4, 3, 10, 17, 24, 31 -4, 7, 14, 21, 28, 35 3, 10, 17, 24, 31, 38 0, 7, 14, 21, 28, 35
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It's A, right?
@phi
your notation is slightly wrong I'll assume \[a_{1} = -4 ... and ....a_{n} = a_{n -1} + 7\] so you add 7 to the previous term -4, -4 + 7, (-4 + 7) + 7, (-4 + 7 + 7) + 7, .... just follow the pattern
and yes it is A
Okay thank you
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