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Trigonometry
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solve: 3sin(2x) - 1 = 1
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do you want the answer in radians or degrees?
degrees
approximately 21 degrees
add 1 to both sides and you get\[3\sin 2x=2\]
divide each side by 3 and you get \[\sin2x=\frac{ 2 }{ 3 }\]
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yes i understand that
do inverse sin on both sides and you get \[2x \approx 42\]
the angle is 2x not 2x -1
then divide both sides by 2 and you get x=21
well here is the question i have
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yes
i always thought this was ok, but does it work all the time when you need to get the angle out so that you can solve for x
you always thought what was ok
meaning i thought inverse will always work but i wanted to be sure
yeah
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ok thank you for your help.
no problem
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