Math help /geometry ~
@mathsmind
11° 50° 44° 88°
so do you understand it how will get 11 degrees ?
m<(ABC)=m<(ABD) +m<(DBC) = 8x because BD bisect <(ABC) so than m<(ABD) = m<(DBC) = (8x)/2 = 4x but we know that m<(ABD) =2x +22 so than we get that 2x +22 =4x so 22=4x-2x 22=2x x=22/2 x=11 hope so much that is understandably ok ?
Wow, thank you ! that was actually vary well explained and easy to fallow (:
ok good luck bye
can you help me with the terms of these? i understand how they am not sure of what the steps are "called"
so there note the same like a wann being step 1 b ----- step 2 ..... .... ok ?
AC = AB + BC AC= 32 AB= 2x BC= 6x +8 so than we can writing 32 = 2x +6x +8 32 -8 = 2x +6x 24 =8x 24/8 = x x=3
i already know that ^. see this is the problem after it and im not sure if this is what they want you to do. 21. Complete the two-column proof. Given: Prove:m∠3 = 70º Given m∠2 = m∠4 Definition of congruent angles m∠4 = 110º b. ________ ∠3 and ∠4 are a linear pair Definition of a linear pair (shown in diagram) ∠3 and ∠4 are supplementary Linear Pair postulate m∠3 + m∠4 = 180º c. _______ m∠3 = 70º d. ________
@mathsmind ?
i just cam u need any assistance
@o.Ohuh
Yea i still dont really understand
well u need to remember the thorems
angle 4 is 180-70, two angles on a straight line, what do u call that?
two angles are =180 degree
the main question is how to find angle 4
are u here?
have u heard of a term called corresponding angles?
when u r backlet me know? ok
Hi sorry , a corresponding angle is when 2 lines are crossed by another line. and If the two lines being crossed are Parallel Lines, then the Corresponding Angles are equal. riight?
@mathsmind
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