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Two sides of a parallelogram measure 60 centimeters and 40 centimeters. If one angle of the parallelogram measures 132, find the length of each diagonal.
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i know one length is 91.7
|dw:1362209766659:dw| Hope this might help
about 91.7 cm and 44.6 cm or about 91.7 cm and 54.2 cm
Sorry the 130 should be 132
if one angle is 132 the other is 48 as the angles are cointerior in parallel lines Then you will have 2 triangles and you will need to find the diagonal using the law of cosines |dw:1362210035754:dw| \[a^2 = 40^2 + 60^2 - 2 \times 40\times 60 \times \cos(132)\] and the other triangle is |dw:1362210064192:dw| \[d^2 = 40^2 + 60^2 - 2 \times 40 \times 60 \times \cos(48)\] hope this helps
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