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Mathematics 4 Online
OpenStudy (anonymous):

Calculate the limit of Xn=sin sqrt(n+1)−sin sqrt (n), n→∞

OpenStudy (anonymous):

Xn=sin sqrt(n+1)−sin sqrt (n), n→∞ Infinity +1 is still infinity. The 1 really doesn't matter. Sqrt of infinity is still infinity. so then you have sin(infinity)-sin(infinity), which cancels out to zero.

OpenStudy (anonymous):

Does that help?

OpenStudy (anonymous):

Thank you.

OpenStudy (zarkon):

While the answer is zero in this case the reasoning is not sound.

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