What is the simplified form of 4x^2-20x+25/2x-5
and what are the restrictions plz explain so i can do the rest of examples
that doesnt help i wasnt asking for that i want an explanation
oh
yea so can you explain
so u want to kno how to simplify that right
yes
like evertyhing how to get the restritiond
restrictions*
yeah im not sure @ZeHanz any ideas
how did you get the answer you gave me
im that type of person where i dont want food sped to me on a silver platter
i want a explanation
plz?
If you want to simplify a fraction, there has to be some common factor in numerator and denominator. The denominator has only 2x-5 so that is the only factor. It is a good idea to factor the numerator then. Hopefully, 4x^2-20x+25 will contain 2x-5 as a factor, so we can simplify!
ok the restrictions
What did you have in mind?
know i wanna know how to get that i dont understand that
no*
Or, to be more specific, in the kind of form you are dealing with, what kind of restriction could you think of?
x not equal to 5/2
There you go!
i mean negative
ok
i meant x not equal to -5/2
Stay positive on this one, dear!
just explain
im on negative
2*(-5/2)-5=-5-5=-10 >> dividing by -10 is not a problem.
i just dont understand the restrictions part
look here are the answers choices
We don't need choices, we need to think. Why would there be any restrictions? Let's look at the numerator: can you calculate 4x²-20x+25, no matter what x is?
theres restrictions on my problem and i dont even know what the heck that is
thats the part thats confusing me can you kindly explain that part
I'm trying: Why would there be any restrictions? Let's look at the numerator: can you calculate 4x²-20x+25, no matter what x is?
yes its 2x-5
No, the numerator is 4x²-20x+25. Can you calculate 4x²-20x+25, no matter what x is?
no
that doesnt make sense isnt there suppose to be =0
4x^2-20x+25=0 can you calculate that you meant
Why? All you need to do is the following: 1. calculate 4x². can do that for every x! 2. subtract 20x. no problem 3. add 20. no problem. See? You can put ANY number in 4x²-20x+25, no matter what x is! There will always be an outcome. Denominator 2x-5: exactly the same: we can double the value of ANY number and then subtract 5. Yet, there IS a value of x may may NOT use if we have to do with 4x²-20x+25 and 2x-5 what has to be done: we have to divide 4x²-20x+25 by 2x-5. When can you not divide?
ok you get 2x-5
when you divide but still your not explaining me how to get restrictions
I am doing it all the time, but you have to read carefully what I wrote. We choose some (any) x. All we have now is two numbers: the value of 4x²-20x+25 and the value of 2x-5. Now we need to divide the two. You must ask yourself this question: can I always divide two numbers, no matter what the numbers are?
yes
So tell me how much is 3/0
0
If that was true, then I could check this calculation in this way: 18/3=6, so 6*3 = 18, right? So if 3/0 = 0, then 0*0=3?
no
0*0 doesnt equal 3
Of course not! It is worse than that: if 3/0=a, then a*0=3. There isn't a number to be found that multiplied with 0 would give 3! So: 3/0 cannot be done. That's the restriction.
You always have to remember this very important fact: You cannot divide by zero!
ok can you use that example in the problem i gave u and maybe i will understand it
In the problem you have to divide by 2x-5. If you set x such that 2x-5 becomes 0, you have a problem, because you cannot divide by 0. So when IS 2x-5=0? Well, then 2x=5, and x=5/2. So the one and only number that you may NOT use in this division, is x =5/2, because it would lead to division by 0.
and you can divide by zero 5/0=0
0/5=0
dividing 0 by 5 is no problem. Check: 0/5=0, because 5*0=0 OK
whats 0/5
its 0 isnt it
Yup!
ok your still not making sense
did you explain it how the problem i gave u
Well, I am: 0/5=0 because 5*0=0. Seems senible enough!
ok i understand that but how does that help me with my problem
A lot. In your problem you have to do 2 things: 1. Simplify the fraction. (I gave you a hint way up in this topic) 2. State restrictions on the variable. We found this restriction: x may not be 5/2. So you still have to do 1., but your questions focused on 2. all the time...
im asking how to get number 2
and your giviving me examples off other things
We have done that. Restriction found: x may not be 5/2.
0/5=0 3/0=0 etc.
how
your just giving me the answer explain
plz?
the restrictions
i dont get
i get everything else
can you put that in math form plx
oh
and that would be x not equal to 5/2
I live in USA, but im jamaican
can you explain
read the problem cause im getting different answers
which is
x not equal to -5/2
can i just solve for x and set =0
its -2x-5=0
but if i solve i still get 5/2
x not eqqual to 5./2
ok
after an hour i finally get it
Thank you so Muhc
ok
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