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Mathematics 10 Online
OpenStudy (anonymous):

can 9√3 ÷ 2 be simplified?

OpenStudy (anonymous):

Nope.

OpenStudy (anonymous):

really? thank u:)

OpenStudy (anonymous):

so i would just leave it like that?

OpenStudy (anonymous):

No because you cannot take the sqrt of 3 nor does 9/2 simplify at all.

OpenStudy (anonymous):

oh.. ok thank u!:)

OpenStudy (anonymous):

So looks like leave it like that

OpenStudy (anonymous):

ok.. what would it be if it was 9√3 ÷ 2 times 3?

OpenStudy (anonymous):

@sask54 ?

OpenStudy (anonymous):

Well that could be written as \[\frac{ 3* 9\sqrt{3} }{2 }\] which becomes...

OpenStudy (anonymous):

27 √3 over 2?

OpenStudy (anonymous):

Yes! And can you see any way for that to simplify?

OpenStudy (anonymous):

does the 27 somehow cross out?

OpenStudy (anonymous):

Nope, it is odd so not divisable by 2

OpenStudy (anonymous):

so what is it divisible by? 3?

OpenStudy (anonymous):

No, that was a trick question I suppose. It's as simplified as can be your final asnwer is 27 rt 3 over 2

OpenStudy (anonymous):

thank u so much!:)

OpenStudy (anonymous):

No problem!

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