Question

The capacitance of a parallel plate capacitor
\[C=\frac{Q}{V}\]
\[dV=-\int Edr\]
\[E=\]

Answer 1

should I use gauss's law to find the electric field?

Answer 2

yes .. use the gauss law. consider a single plate first.

Answer 3

\[\oint E dA=\frac{Q}{\epsilon_0}\]

\[Q=\sigma A\]
\[EL^2=\frac{Q}{\epsilon_0}=\frac{\sigma L^2}{\epsilon_0}\]
\[E=\frac{\sigma}{\epsilon_0}\]

Answer 4

since we have two plates do we use \(2\sigma\)?

Answer 5

yeah yeah ... that;s the way ...
let me add few things ...