assume the Pi = 101 kpa an vi= 10.0l if pf=43.0 kpa what is v
Pi*Vi = Pf * Vf 101*10.0 = 43.0 * x solve for x
how do you find out what x is ? im just learning this
you divide both sides by 43.0 to isolate x
so i just do 43.0 divided by 43.0 ?
yes on the right side do the same on the left side
um well what sides? sorry... im really confuessed because its only on a piece of paper my teacher wrote it. its only the problum
101*10.0 = 43.0 * x 101*10.0/43.0 = 43.0 * x/43.0 101*10.0/43.0 = 1x x = 101*10.0/43.0 x = ???
23.488372093?
you got it
thank you!
you're welcome
do u know how to do (9x10 power of -1) x 3 x 10 power of 10 )?
multiply the bases (9 and 3) add the exponents (-1 and 10) then convert to scientific notation (if necessary) or standard form
its standard form how do u write that 9x3=27 an -1 +10 =9
so it would be 27 x 10^9 you can convert to scientific notation or standard form if you want
the answer in scientific notation would be 2.7 x 10^10 in standard notation, it would be 27,000,000,000 (which is the number 27 billion)
thank you i have a few more questions if u dont mind
if electirc forces are so strong why dont i notice them acting on everything around me ? a friend asks how do i respond ? thats the question
well there's a balance in forces that keeps everything from either flying apart or pulling together and collapsing in on itself
you only see an imbalance in force when you see things like electricity or magnetism
okay thank you show how multiply both sides of the acceleration equation a= fnet (over) m by m results in the net force equation fnet+ma
I'm using f instead of fnet a = f/m a*m = f/m * m ... Multiply both sides by m. a*m = fm/m a*m = f*1 a*m = f f = a*m f = ma
i dont get it ......
where are you stuck?
all of it i dont know what m is ? or like any of it?
there's no need to know m
you just need to rewrite a = f/m into f = ma
ohh okay i get it . hiw do u do calculate the acceleration of a 25 kg object that is moved with a force of 300 n sorry i have to have this an an whole other book done in an hour
f = ma 300 = 25*a solve for 'a'
12?
good, the acceleration is 12 m/s^2
okay thanks the mass of the following box is 120.00g calculate the destiny the box has a 5cm 6 cm an a 4 cm by it ?
first find the volume of the box
120 ?
now divide the mass by the volume
D = M/V D = 120/120 D = 1
so the density is 1 gram per cubic cm
so is that the answer ?
theres another question the normal states of matter are solid liquid gas a friend says then there is a really uncommon state called plasma how would you respond to this claim
I would respond by showing him/her this link http://en.wikipedia.org/wiki/Plasma_%28physics%29
this link shows there are tons of places where you would find plasma so it's not so rare
okay hah thanks evaluate this statment the object is in motion in a stright line and it is moving with a constant speed that must mean that no force is acting on it
ok just say whether it's true or false?
is it false ?
why is it false?
because wouldnt sommething have to be moving it ?
think of it out in outerspace away from any planet
it's far from any forces and it moves in a straight line at the same speed
well then its true
nothing is speeding it up or slowing it down nothing is changing its direction
so there are no forces acting on it
yes it's true
okay well how do u do this it says place a nymber of the law of motion w=in the blank next to rhe examples of the law giving the first on is fnet =ma
2 seven ball is struck by the cue ball 3 an air filled balloon is released 4 you push on a box of books
not sure what this is saying
something seems missing
ill type it again hold on
place the number of the law of motion in the blank next to the examples of the law giving the examples are
*fnet =ma * seven ball is struck by the cue ball * an air filled balloon is released *you push on a box of books
oh i gotcha, ok one sec
fnet =ma is definitely the second law of motion
even ball is struck by the cue ball sounds like the third law of motion
not sure about the third one but you push on a box of books also sounds like the third law of motion
thank you! how many cubic centemeters dose 1.304L have
check this link out http://www.google.com/search?hl=&q=1.304+L+to+cubic+cm&sourceid=navclient-ff&rlz=1B3GGLL_enUS420US420&ie=UTF-8
the question is the distance from the launch site to the observation is 120 meters calculate the adverage height a if the obtained altimeter reading from 4 observations sites were the following
something seems missing here
oh and the pic is mirrored lol can you fix that please?
yes
can u see the shpae ill typer the answers
yeah i'll just try to reverse it in my head
* 36.5 *35.0 *40.0 *38.0
question is
the distance from the launch site to the observer is 120 meters calculate the average height a , if the obtained altimeter readings from 4 observation sites were the following
do u got it?
one sec
okay
does it give you answer choices?
yes its 36.5 , 35.0 40.0 or 38.0
those are the heights though right?
well it says derees after the numbes
oh nvm, ok one sec
ok
(120*tan(36.5) + 120*tan(35) + 120*tan(40) + 120*tan(38) )/4 = 91.8166161276659 which is roughly 91.82 meters
so which one is it ?
91.82 if you're rounding to two decimal places
ohhh gotcha
what bout this
if a current flowing through a light buld is 0.75 a an the voltage diffrence is across the light bulb is 120v how much resistance does the light bulb have
V = I*R 120 = 0.75*x solve for x
61 ?
make a general statement about the facts that increases resistance
120 = 0.75*x x = 120/0.75 x = ???
isnt it 61 ?
no
then idk
120/0.75 = 160
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