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find the maximum y value on the graph y=f(x) f(x)=-x^2=8x+6
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@vortish f(x) = -x^2 = 8x+6 ??????? is it right?
no it is f(x)=-x^2+8+6
ok take the first derivative of f(x) and put the derivative equal to zero and tell me what u r getting?
i dont understand that can you draw it and then i will be understand what your asking pls
cool it is given f(x) = -x^2+8x+6 can u do the differentiation of f(x) w.r.t x ?
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no I always had trouble with these expressions
fine as we know d/dx ( x^n) = n x^(n-1) and d/dx(constant) = zero so f ' (x) = -2x+8 did u follow this step?
yup
now put f '(x) = o and tell me what is the value of x u r getting?
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