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Mathematics 18 Online
OpenStudy (firejay5):

What's the inverse function of 1/5x -7?

OpenStudy (experimentx):

Can you isolate 'x' from below? \[ y = \frac{1}{5x-7}\]

OpenStudy (firejay5):

that's the actual function

OpenStudy (experimentx):

whateve ... can you isolate x from there?

OpenStudy (firejay5):

Do you know @genius12

OpenStudy (anonymous):

\[y=\frac{ 1 }{ 5x-7 }\]To get the inverse, we switch the x with the y and solve for y, like this:\[x=\frac{ 1 }{ 5y-7 }\rightarrow 5y-7=\frac{ 1 }{ x } \rightarrow y=\frac{ \frac{ 1 }{x }+7 }{ 5 } \rightarrow y=\frac{ \frac{ 7x+1 }{ x } }{ 5 } \rightarrow y=\frac{ 7x+1 }{ 5x }\]

OpenStudy (anonymous):

ExperimentX is correct|dw:1362341025931:dw| To make a black box that works the other way, rearrange so that x is is subject of the equation.

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