Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Tell whether each situation is a permutation or combination. then solve. 1.how many ways can 10 students line up for lunch?

jimthompson5910 (jim_thompson5910):

order matters, so you would use a permutation

jimthompson5910 (jim_thompson5910):

if order didn't matter, then you would use a combination

jimthompson5910 (jim_thompson5910):

Ironically, a combination lock for a locker is actually a permutation lock since order matters. Ex: the "combination" 1-19-23 is really a permutation since order matters and that's not the same as 19-1-23 So unfortunately this adds a lot of confusion

OpenStudy (anonymous):

if each student is unique, then it would be a permutation. However, if each student is just considered the same as every other student, then it would be a combination.

jimthompson5910 (jim_thompson5910):

So because you're using a permutation, you would use this formula n P r = (n!)/((n-r)!) where in this case, n = 10 and r = 10

OpenStudy (anonymous):

Thanks! Will answer the questions first then I'll let you guys check. Is it okay?it's my firs time here

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

yes that's a great idea so what did you get for this one?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!