A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = 0.04x+ 8.3x + 4.3, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

Question

anonymous · Answer

Are you sure the equation is not $$y = 0.04x^2 + 8.3x + 4.3$$?

anonymous · Answer

thats the equation sorry

anonymous · Answer

So you know that when y is equal to zero it is on the ground, correct? It is equal to zero in two occasions, once before it is launched and once when it lands. So you can set y equal to zero $$0 = 0.04x^2 + 8.3x +4.3$$ and solve for x.