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Mathematics 6 Online
OpenStudy (anonymous):

how would you solve the given trigonometric equation exactly on 0< or = theta<2pi sec^2(2theta)-(4/3)=0

OpenStudy (raden):

first, factor out of it : sec^2(2x)-(4/3)=0 (sec(2x) + 2/sqrt(3))(sec(2x) - 2/sqrt(3)) sorry, i assuming theta be x so that typing be easier

OpenStudy (raden):

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