Question

Help!

Answer 1

5. What is an equation of a parabola with the given vertex and focus? vertex: (5, 4) ; focus: (8, 4)

Answer 2

If you say so.

Answer 3

Can u help @TrashMan914 @ZeHanz

Answer 4

Hello?

Answer 5

I am present.

Answer 6

can u help

Answer 7

Working on it.

Answer 8

@TrashMan914 do you have it?

Answer 9

@satellite73

Answer 10

@ZeHanz can u help

Answer 11

Formula to use is: (y-b)²=2p(x-a)².
Vertex: (a, b), Focus (0.5p, b)

Answer 12

would it be x= or y=

Answer 13

Sorry, typed a ² too much:

(y-b)²=2p(x-a)

This is when the line of symmetry is horizontal, which it is in this case, because the vertex
and the focus have the same y-coordinate.

Answer 14

So whicj would it be?
y =1/12(x + 4)2 – 5
x =1/12(y + 4)2 – 5

Answer 15

*which

Answer 16

You fill in the points and the you have to convert yourself.
Vertex = (5, 4), so a = 5, b = 4.
Focus = (8, 4) so 0.5p=8

Put all these things in (y-b)²=2p(x-a) and rearrange to see what answer you have to choose.

Answer 17

is it A. that was my orignial answer

Answer 18

Well, I do not get to that: (y-4)²=2*2*8(x-5),
so (y-4)²=32(x-5)

x-5=1/32 (y-4)² and thus x = 1/32 (y-4)² + 5

Answer 19

could the 1/32 be simplified to 1/12

Answer 20

@ZeHanz

Answer 21

1/32 cannot be simplified to 1/12.

Answer 22

but 1/32 isn't any of my choices

Answer 23

x = 1/32 (y-4)^2 + 5 is not a finished equation. You need to solve it.

Answer 24

but it looks exactly like my choices except for the 1/32

Answer 25

x =1/12(y – 4)2 + 5
y =1/12(x + 4)2 – 5
x =1/12(y + 4)2 – 5
y =1/12(x – 4)2 + 5
@trashman914 these are the choices

Answer 26

You are right! I´ve made a mistake in the value of p.
I would put my money on A.
Gonna recalc to see what I did wrong...

Answer 27

oh ok... thanks