Question

x^2+6x=-9 solve by factoring

Answer 1

you need to put -9 to left side. You get:

x^2+6x+9=0 Do you know formula:

\[(a+b)^{2}=a ^{2}+2ab+b\]

Answer 2

Yes but it still kind of confuses me :/

Answer 3

Do you agree, that x^2+6x+9=0 can be written as (according to the formula):
\[(x+3)^{2}=0\]

Answer 4

Yes

Answer 5

so, we have just factorised. Now we need to solve it

\[(x+3)^{2}=0\] when
\[x+3=0\]
x=-3

Answer 6

Would it be +/- 3 ?

Answer 7

No, it wouldnt. try to put "3" in the eq and you will get

\[(3+3)^{2}=0\]
\[6^{2}=0\]
\[36\neq0\]
And when you put "-3" in the eq, you get:

\[(-3+3)^{2}=0\]
\[0^{2}=0\] \[0=0\]

Do you understand it?

Answer 8

Yes thank you so much

Answer 9

You are welcome!