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Solve. 81^x = 27^x + 2 My answer: x = 2 x = 1 x = 2 x = 5 x = 6
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ok that was wrong lets try again \[3^{4x}=3^{3x+6}\]
how would I solve that?
since \(3^4=81\) and \(27=3^3\)
since we arranged it so the bases are the same, then the exponents must be the same that was the point of making the bases equal solve \[4x=3x+6\]
oh, okay, I see now!!!
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ok good!
I got 6 as my answer on my paper
yes that should be right you can check it if you have a calculator that is check that \(81^6=27^8\) it is too much to do by hand, they are huge numbers
okay i will right now
thank you so much
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yw
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