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OpenStudy (anonymous):
simplyfy expression
OpenStudy (anonymous):
@Ceann
OpenStudy (anonymous):
This'll be my last one. Not to be greedy, but can you give me the medals for the ones I finished?
OpenStudy (anonymous):
Starting with form \[\frac{7}{n-3}+\frac{n}{n+3}\]
Do conjugates again.
\[\frac{7}{n-3}(\frac{n+3}{n+3})+\frac{n}{n+3}(\frac{n-3}{n-3})\]
Simplify.
\[\frac{7n+3}{n^2-3}+\frac{n^2-3n}{n^2-3}=\frac{n^2+4n+3}{n^2-3}\]
There's a (n+3) in there that cancels to give you
\[\frac{n+3}{n-3}\]
All done!
OpenStudy (anonymous):
your great thanks
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OpenStudy (anonymous):
for some reason that one come out wrng too
OpenStudy (anonymous):
@EvrydayAzn
OpenStudy (anonymous):
Ceann explination is pretty clear
OpenStudy (anonymous):
what exactly are you having problems with?
OpenStudy (anonymous):
that answer came out wrong
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OpenStudy (anonymous):
can you like show me the work? so I can see the steps
OpenStudy (anonymous):
can you like take a picture and upload it?
OpenStudy (anonymous):
i dont know how to do this one
OpenStudy (anonymous):
which one?
OpenStudy (anonymous):
7/n-3 + n/n+3
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