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Algebra 10 Online
OpenStudy (anonymous):

7/n-3 + n/n+3

OpenStudy (anonymous):

simplyfy expression

OpenStudy (anonymous):

@Ceann

OpenStudy (anonymous):

This'll be my last one. Not to be greedy, but can you give me the medals for the ones I finished?

OpenStudy (anonymous):

Starting with form \[\frac{7}{n-3}+\frac{n}{n+3}\] Do conjugates again. \[\frac{7}{n-3}(\frac{n+3}{n+3})+\frac{n}{n+3}(\frac{n-3}{n-3})\] Simplify. \[\frac{7n+3}{n^2-3}+\frac{n^2-3n}{n^2-3}=\frac{n^2+4n+3}{n^2-3}\] There's a (n+3) in there that cancels to give you \[\frac{n+3}{n-3}\] All done!

OpenStudy (anonymous):

your great thanks

OpenStudy (anonymous):

for some reason that one come out wrng too

OpenStudy (anonymous):

@EvrydayAzn

OpenStudy (anonymous):

Ceann explination is pretty clear

OpenStudy (anonymous):

what exactly are you having problems with?

OpenStudy (anonymous):

that answer came out wrong

OpenStudy (anonymous):

can you like show me the work? so I can see the steps

OpenStudy (anonymous):

can you like take a picture and upload it?

OpenStudy (anonymous):

i dont know how to do this one

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

7/n-3 + n/n+3

OpenStudy (anonymous):

do you know what a conjugate is?

OpenStudy (anonymous):

no i dont remember any of this

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