Describe how the graph of the function y=1.5sin(4x) is related to the graph of y=sin(x). Then, graph two periods of y=1.5sin(4x). ***Idk how to solve this at all :( and also, i will attach the graph it gives me to draw/graph the periods on! :D @jim_thompson5910 :) thankss :)
here is what I'm supposed to graph that second part on... but first i'm supposed to describe how to graph it?? :/ idk how thoo :(
In general, we have this y = A*sin(Bx - C) + D The amplitude is |A| The period of that equation above is T = 2pi/B
In the case of y = sin(x), the amplitude is |A| = |1| = 1 and the period is T = 2pi/B = 2pi/1 = 2pi
so what's the amplitude and period of y=1.5sin(4x)
urmm 0? :/ ***not too sure.. i plugged into my calc.. am i supposed to do that?
what's the amplitude of y=1.5sin(4x)
idk :( i got 0? but i don't think i did it right...
compare it to y = A*sin(x)
what is the value of A?
A=1? :/
idk im so sorry :( I'm super lost :(
compare y = 1.5sin(4x) to y = A*sin(Bx) you'll see that A = ?? and B = ??
ohhh A=1.5?? and B=4 ??
so the amplitude is 1.5 the period is 2pi/B = 2pi/4 = pi/2
so basically the period is pi/2?? that is the most simplified form?
how would i describe that entire thing though?? like all of it?? :/ sorry, cuz all the jumbled up ness is confusing me even more :( sorry bout that!! :/
yeah it's pi/2, I would suggest learning the general form y = A*sin(Bx - C) + D and practicing with it a bit more
okay :) so is that how they are related?? :/ the amplitude and the period?? :/
the amplitude tells you how tall the overall graph is (think of it like the height of the wave)
the period tells you when and where the graphs does a complete cycle and starts to repeat itself over again
*graph does*
or maybe do u think it would be better if i studied up a bit more on this and then came back tomorrow?? :) do u think that would be better? that way i understand it more and we can finish the whole describing thing and the graphing part?? so that it isn't just you giving me the answer? :) and ohhh i see haha that clears it up a lot :P lol typos... :/
like after i study it a bit more and think i get it better, i will reply sometime tomorrow and we can take it from there? :)
what do u thinK? :D
that sounds like a good idea
okay, awesome! i will reply to this later tomorrow then :)see ya manana hopefully!! :)
and hopefully i will understand this concept a lot better!! :D
see you later as well, have a good night
thanks! you too! :) see yaaaa :D
okay, so i studied up a bit on it and i think i get it more... but i still don't understand what the amplitude or what the two periods of y=1.5sin(4x) are... nor do i know how to describe how the graph of that function is related to the graph of y=sin(x).... I'm still kinda confused ;( im sorryyy.. do u think u can explain it and how to solve this problem?? i am utterly stuck :(
there's only one period, and it's pi/2 remember how we got this?
yes, but kinda ish... so the problem asks this: Describe how the graph of the function y=1.5sin(4x) is related to the graph of y=sin(x). Then graph two periods of y=1.5sin(4x). ***Graph according to the graph that I will attach :) BUt I'm confused... it says to graph TWO periods, but you say there is only one? :/ and how do i describe it and how do i graph it? :/
lol random side note...someone just sent me a message but they have it set up to where I can't send a message back...how frustrating and confusing...anyways, sry for the random thought when it says graph two periods, it means graph two complete cycles. The graph of y = 1.5sin(4x) has a period of pi/2. To graph two complete cycles, you would start at x = 0 and go to x = pi/2 to do one complete cycle, then you would go from x = pi/2 to x = pi to do a full second cycle. Make sense?
so let's say for example this is the graph of y = 1.5sin(4x) (it's not, let's just say it is) |dw:1362519709185:dw|
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