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Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66. 70 72 111 114
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first, a27 = 66 means a1 + (27-1)d = 66 -12 + 26d = 66 solve for d
3
yep.. correct
k
now, to get a42 use the formula : an = a1 + (n-1)d a42 = -12 + (42-1)3 a42 = -12 + 41(3) = ... ?
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got it ?
what's 41 times 3 ..... then subtracted by 12
111, !
cool :D
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