Determine where the given function is increasing and decreasing. f(x)=(x+3)^(2/3)-7
increasing when f ' > 0 decreasing when f ' < 0
First you have to start with finding the derivative
I got the derivative its f'(x)= 2/3(x+3)^(-1/3) but now im lost.
now you have to find the critical point. Do this by finding solving the derivative = 0
yeah but dont you have to factor that first then make it = 0 ?
probably and that's where it gets complicated. I know that's the point where I start having trouble. I'm pretty much doing the same stuff you're doing right now just a little further ahead
yeah same here that is where I am stuck. I am in Business Calc.
you could try this. unfortunately it's not really going to help you if you need to learn it but it should give you the answer http://www.wolframalpha.com/widgets/view.jsp?id=a2bc91cf95686cd1a6ae16e6293626f2
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