Question

am i got the right answer? tangent line

Answer 1

find an equation of the tangent on the curve at the given point.
\[y(x)=\frac{ x^2-1 }{ x^2+1 } \] (0,1)

Answer 2

I have got \[y prime= \frac{ 4x }{ (x^2+1)^2 }\]

Answer 3

I know that I did something wrong becasue when I inserted zero into x, the answer is zero...

Answer 4

@AravindG

Answer 5

no you didnt make a mistake !!

Answer 6

you are looking for equation of line , so y prime will be the slope and (0,1) is point on the line

Answer 7

use slope point form to get the answer and be happy ^_^

Answer 8

understood ?

Answer 9

Oh! y prime is the slope?

Answer 10

wait a sec i am confused now .. 1 min

Answer 11

y-y=m(x-x)
M is the slope which is the y prime?

Answer 12

ok now i get it

Answer 13

put x=0 in y prime that will be the slope at that point

Answer 14

then i get zero?

Answer 15

dont mind the 1 in ordered pair it represents a point and does not relate to y prime

Answer 16

so put zero (x) in to the equation? i get zero for the slop!

Answer 17

exactly !!

Answer 18

so what are you left with ?

Answer 19

oh, thats less exciting..
y-1=0(x-0)?

Answer 20

yep !

Answer 21

thank you although i was excepting more big numbers. haha

Answer 22

thanks your help!!!

Answer 23

i just checked this with a graphing calculator !