Question

Whats the derivative of tan^theta - theta?

Answer 1

\[y=\tan^\theta-\theta\] Is this what you mean?

Answer 2

yes

Answer 3

So we are taking tangent of -theta to the power of theta.

Answer 4

Im supposed to differentiate \[g(\theta)=e^{\theta}(\tan \theta- \theta)\]

Answer 5

\[g'(\theta)=[e^\theta*(\tan(\theta)-\theta)]+[e^\theta*\sec^2(\theta)]\rightarrow g'(\theta)=e^\theta[(\tan(\theta)-\theta)+(\sec^2(\theta)]\]
@meaghan716

Answer 6

Btw, I'm assuming that theta is independent and not a function of another variable.

Answer 7

In the second set of brackets on the left you need
\[[e ^{\theta}*(\sec ^{2}\theta - 1)]\]