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OpenStudy (anonymous):
Let f(x)=9x^2
Enter the slope of the line tangent of f(x)at x=3
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OpenStudy (anonymous):
slope?
OpenStudy (anonymous):
find f'(x)
OpenStudy (anonymous):
No I have to find slope
OpenStudy (anonymous):
yes i know find the derivative of f(x) it will give u the slope ...
OpenStudy (anonymous):
oh gotch I am really confused with this problem so I have no idea where to start
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OpenStudy (anonymous):
i will show u how to do it
OpenStudy (anonymous):
\[f(x)=9x^2 \longrightarrow f \prime (x)=18x\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
now f'(3)=18x3
OpenStudy (anonymous):
so one of the meanings of derivative is a slop
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OpenStudy (anonymous):
slope*
OpenStudy (anonymous):
when u differentiate a function that means u found the slope of the tangent
OpenStudy (anonymous):
keep that in ur mind at ur level
OpenStudy (anonymous):
ok so then is the slope 18
OpenStudy (anonymous):
now it says at 3
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OpenStudy (anonymous):
slope is 18x
OpenStudy (anonymous):
y =mx recall
OpenStudy (anonymous):
yes got that
OpenStudy (anonymous):
So then I just have to say that my answer is 18x correct?
OpenStudy (anonymous):
m=18 in general
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OpenStudy (anonymous):
but it is asking u the slope at x=3
OpenStudy (anonymous):
18 times 3
OpenStudy (anonymous):
oh so then what so I do
OpenStudy (anonymous):
so then slope =54
OpenStudy (anonymous):
yep
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OpenStudy (anonymous):
oh ok thanks
OpenStudy (anonymous):
you're welcome!
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