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Mathematics 15 Online
OpenStudy (anonymous):

Let f(x)=9x^2 Enter the slope of the line tangent of f(x)at x=3

OpenStudy (anonymous):

slope?

OpenStudy (anonymous):

find f'(x)

OpenStudy (anonymous):

No I have to find slope

OpenStudy (anonymous):

yes i know find the derivative of f(x) it will give u the slope ...

OpenStudy (anonymous):

oh gotch I am really confused with this problem so I have no idea where to start

OpenStudy (anonymous):

i will show u how to do it

OpenStudy (anonymous):

\[f(x)=9x^2 \longrightarrow f \prime (x)=18x\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

now f'(3)=18x3

OpenStudy (anonymous):

so one of the meanings of derivative is a slop

OpenStudy (anonymous):

slope*

OpenStudy (anonymous):

when u differentiate a function that means u found the slope of the tangent

OpenStudy (anonymous):

keep that in ur mind at ur level

OpenStudy (anonymous):

ok so then is the slope 18

OpenStudy (anonymous):

now it says at 3

OpenStudy (anonymous):

slope is 18x

OpenStudy (anonymous):

y =mx recall

OpenStudy (anonymous):

yes got that

OpenStudy (anonymous):

So then I just have to say that my answer is 18x correct?

OpenStudy (anonymous):

m=18 in general

OpenStudy (anonymous):

but it is asking u the slope at x=3

OpenStudy (anonymous):

18 times 3

OpenStudy (anonymous):

oh so then what so I do

OpenStudy (anonymous):

so then slope =54

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

oh ok thanks

OpenStudy (anonymous):

you're welcome!

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