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4x2 + 4x + 1 = (2x + 1)2
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true of false
Is it : \[\large{4x^2 + 4x + 1 = (2x+1)^2}\] or \[\large{4x^2 + 4x + 1 = (2x+1)2}\] ?
the 1st one
OK so do you know the formula for \(\large{(a+b)^2}\) ?
i think so
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What is it ?
ummmm
this is hard
@Mertsj will continue to help you as I have got urgent work Thanks a lot Mertsj
yw
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(a+b)^2 = a^2+2ab+b^2
We suspect our trinomial is of this form since the first term is a perfect square and the last term is a perfect square.
So then we think: if 4x^2 is a squared, then a is 2x. If b^2 is 1 then b is 1 and 2ab is 2(2x)(1) which is the middle term.
So we know we have a trinomial square and the factors are (2x+1)^2
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