solve the system of equations y = X^2-6x-2,
4y-x=1

Question

solve the system of equations y = X^2-6x-2,
 4y-x=1

kropot72 · Answer

One way to solve is to use substitution.
The equation 4y - x =1 can be rearranged to give x in terms of y as follows:
Subtracting 4y from each side gives
-x = 1 - 4y
Multiplying both sides by -1 gives
x = 4y - 1.................(1)
Now the value for x in equation (1) can be substituted in the quadratic. Can you do that?

anonymous · Answer

yeah but when i substitute this in i get a answer that i cannot factor and that is where i get stuck

anonymous · Answer

quadratic formula always works

kropot72 · Answer

Substituting for y did you get
$$y=16y ^{2}-8y+1-24y+6-2$$

anonymous · Answer

yeah i did get that

kropot72 · Answer

So now we can form a quadratic and solve it. As @satellite73 pointed out all quadratics can be solved (by the formula if necessary).
$$16y ^{2}-33y+5=0$$
Can you solve this using the formula?

anonymous · Answer

yes thank you :)

kropot72 · Answer

You're welcome :)