Question

how do you solve this equation?
2t^2-2(sqrt2)t+1=0

Answer 1

Use the quadratic formula. It's quadratic in t.

Answer 2

a = 2, b = -2(sqrt(2)), c = 1

Answer 3

how do you do that?

Answer 4

oh okay

Answer 5

what would the answer be?

Answer 6

do you know what the answer would be?

Answer 7

Just substitute the values for a, b and c given by @mathstudent55 into the following formula to solve the equation:
\[t=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]

Answer 8

what answer do you get when you solve that?

Answer 9

@Softballgirl372015 Have you used the quadratic formula?