Draw a line that has the given slope and y- intercept. 7x=5y
slope = coefficient of x y intercept is where x equals zero
Hhhmm still confused as to how I would write it.
Should it look something like this? y=7x+0
well in has to be in linear form so isolate y first 7/5x=y or y = 7/5x therefore your slope would be 7/5
ok so you are dividing 5 by both sides to get rid of y right?
So now I understand how you got 7/5x but now as far as the line how would that appear. I am so lost and this really confuses me. Sorry
it's alright =) write out a x and y intercepts chart and you can see point such as x=5 y=7 x=10 y=14 x=15 y=21 and then you just graph them and draw a line through all the points
May I ask another question?
Write an equation of the line containing the specified point and perpendicular to the indicated line. (-3, 7) Y=5
I came up with -1/5x+ 4/5 is this correct or did I do it correctly
Hello? Are you still there?
yea hold on; it's 3/5 for the last variable I believe other than that everything looks great!
Ok instead of 4/5 it should be 3/5?
yep!
I am not sure what it is that I did wrong. y-y1=m(x-x1)
y-(-2)= -1/5(x-4)
yea that's the correct form; i suppose you just substituted 4 instead of -3 before multiplying it by -1/5
the coordinates are (-3, 7)...
I came up with y+2= -1/5(x-4)
when I multiply -1/5 x -4 i got the answer 0.8
which in fraction I got 4/5 ....is this correct
I am all confused now bec now when I subtract -2 from each side I get -1/2
never mind that was the incorrect equation let me try the correct one which is (4,-2) x=1
How would I solve for this?
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