Question

Does anyone know how to write this in sigma notation?

-2, + 1 + 4 + ... + 13
…

Answer 1

please help!

Answer 2

anyone?

Answer 3

\[\sum_{n=0}^{5} (3n-2)\]

is this you want??
check it please.

Answer 4

from the A.P. series,
a=-2 and d=1-(-2)=3 and N=(l-a)/d=(13-(-2))/3=15/3=5
where a= first term,
l=last term,
N=total number of terms,
d=common difference.
so sum notation will be in general,

\[\sum_{n=0}^{(l-a)/d}(a+nd)\]