Mathematics
15 Online
OpenStudy (anonymous):
How to factorise the following equation:
2x^2 + 5x - 168
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Chad123 Do u know discriminant method?
OpenStudy (anonymous):
Could you please show me?
OpenStudy (anonymous):
for quadratic equation Ax^2 + Bx+ C
Discriminant, D = sqrt( B^2- 4*A*C)
then roots
x1 = (- B + D)/ 2*A and x2 = (-B - D)/2*A
OpenStudy (anonymous):
in the problem it is given 2x^2+5x - 168
So A = 2 , B = 5 and C = -168
first find the discriminant and then roots
OpenStudy (anonymous):
@Chad123 can u do it now?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
What is the capital D?
OpenStudy (anonymous):
D is notation for discriminant
OpenStudy (anonymous):
I'll let you know in a second
OpenStudy (anonymous):
The discrimant equalled square root of 1033
OpenStudy (anonymous):
Could you please show me the steps if you don't mind
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
u r getting wrong
u show ur steps and i will help u in correcting those steps
OpenStudy (anonymous):
Square root 5^2 - 4(2)(-168)
OpenStudy (anonymous):
Is that how you do it?
OpenStudy (anonymous):
yah
OpenStudy (anonymous):
what is your second step?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Adding 25 with 1008
OpenStudy (anonymous):
You get square root of 1033
OpenStudy (anonymous):
4*2*168 = 1344
add 25 with 1344
OpenStudy (anonymous):
No it's equal to 1033
OpenStudy (anonymous):
Sorry your right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so u got sqrt(1369) which is 37
OpenStudy (anonymous):
now can u find the roots?
OpenStudy (anonymous):
And then I plug it into x1 and x2?
OpenStudy (anonymous):
yah u will get your required roots
OpenStudy (anonymous):
You rock man I'm about to give you a medal
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Thanks for all the help
OpenStudy (anonymous):
:-P
OpenStudy (anonymous):
Ciao :)