Question

Tanθ=2. 180*<θ<270*. Cosθ=?

Answer 1

use, \(\sec^2 \theta =1+\tan^2 \theta \)
to find sec theta first.

Answer 2

what u get ?

Answer 3

Same form apply if eg i have csc and cot?

Answer 4

cot is easy
cot x = 1/ tan x
for csc , you first find cot and then use \(\csc^2x = 1+\cot^2x\)

Answer 5

for your initial proble, once you find sec theta,
then cos theta = 1/sec theta
and since in 3rd quadrant cos is negative, add a - *minus* sign to it

Answer 6

Tanθ= 2 180<θ<270. Cosθ=?

Answer 7

yeah, i know the Q, its posted above also :)

Answer 8

did u get the value of sec theta ??

Answer 9

On which quadrant is sec(θ)?

Answer 10

sec θ is just a ratio , it cannot be in any quadrant,
θ is an angle, it can be in a quadrant
180*<θ<270* implies its in 3rd quadrant.